## For $f: \mathbb{R} \to \mathbb{R}$ differentiable, and inverse function which monotonically increasing, Solve: $f'(y)y'=xf(y)$ December 1 1

For $f: \mathbb{R} \to \mathbb{R}$ differentiable, and inverse function which monotonically increasing. I'd love your help with finding $y$ from the following $f'(y)y'=xf(y)$.This is what I did so far:$\frac{f'(y)y'}{f(y)}=x\Rightarrow \frac{f'(y)\fr